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E^(0)Cu//Cu^(+2) = +0.34V, E^(0) Sn//Sn^(+2)= -0.14V E^(0) Zn//Zn^(2+) = -0.76V. Predict spontaneous reaction. |
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Answer» `Zn+CuSO_(4) to ZnSO_(4)+Cu` |
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