1.

E_(1),E_(2) and E_(3) are the emf values of the three galvanic cells respectively (i) Zn|Zn^(2+)(1M)||Cu^(2+)(0.1M)|Cu (ii) Zn|Zn^(2+)(1M)||Cu^(2+)(1M)|Cu (iii) Zn|Zn^(2+)(0.1M)||Cu^(2+)(1M)|Cu Which one of the following is true?

Answer»

`E_(2) gt E_(3) gt E_(1)`
`E_(3) gt E_(2) gt E_(1)`
`E_(1) gt E_(2) gt E_(3)`
`E_(1) gt E_(3) gt E_(2)`.

Solution :`Zn+Cu^(2+)toZn^(2+)+Cu`
`E_(CELL)=E_(cell)^(@)-(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
Thus, HIGHER the value of `[Zn^(2+)]//[Cu^(2+)]`, LOWER is the emf of the cell, `([Zn^(2+)])/([Cu^(2+)])` for `(i)=(1)/(0.1)=10`,
for (ii)`=(1)/(1)=1`, for `(III)=(0.1)/(1)=0.1`
Hence, `E_(3) gt E_(2) gt E_(1)`.


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