E_("cell")^(@) for some half - cell reactions are given below. On the basis of these mark the correct answer - (a) H^(+)(aq)+e rarr (1)/(2)H_(2)(g), E_("cell")^(@)=0.00V (b) 2H_(2)O(l) rarr O_(2)(g)+4H^(+)(aq)+4e , E_("cell")^(@)=+1.23V (c) 2SO_(4)^(2-)(aq) rarr S_(2)O_(8)^(2-)(aq)+2e , E_("cell")^(@)=+1.96V

E_("cell")^(@) for some half - cell reactions are given below. On the

1.	E_("cell")^(@) for some half - cell reactions are given below. On the basis of these mark the correct answer - (a) H^(+)(aq)+e rarr (1)/(2)H_(2)(g), E_("cell")^(@)=0.00V (b) 2H_(2)O(l) rarr O_(2)(g)+4H^(+)(aq)+4e , E_("cell")^(@)=+1.23V (c) 2SO_(4)^(2-)(aq) rarr S_(2)O_(8)^(2-)(aq)+2e , E_("cell")^(@)=+1.96V
Answer» in dilute `H_(2)SO_(4)` solution, hydrogen will be reduced at cathode in cocentrated `H_(2)SO_(4)` solution, water will be oxidised at anode in dilute `H_(2)SO_(4)` solution, water will be oxidised at anode in dilute `H_(2)SO_(4)` solution, `SO_(4)^(2-)` ION will be oxidised to tetrahionate ion at anode ANSWER :A::C