E_(cell)^(Theta) for some half-cell reactions are given below. On the basis of these mark the correct answer. (a) H_((aq))^(+)+e^(-) to (1)/(2) H_(2(g))E_(cell)^(Theta)=0.00V (b) 2H_(2)O_((l)) toO_(2(g))+4H_((aq))^(+)+4e^(-),E_(cell)^(Theta)=1.23V (c) 2SO_(4)^(2-) to S_(2)O_(8(aq))^(2-) +2e^(-),E_(cell)^(Theta)=1.96V

E_(cell)^(Theta) for some half-cell reactions are given below. On the

1.	E_(cell)^(Theta) for some half-cell reactions are given below. On the basis of these mark the correct answer. (a) H_((aq))^(+)+e^(-) to (1)/(2) H_(2(g))E_(cell)^(Theta)=0.00V (b) 2H_(2)O_((l)) toO_(2(g))+4H_((aq))^(+)+4e^(-),E_(cell)^(Theta)=1.23V (c) 2SO_(4)^(2-) to S_(2)O_(8(aq))^(2-) +2e^(-),E_(cell)^(Theta)=1.96V
Answer» In dilute sulphuric acid SOLUTION, HYDROGEN will be reduced at cathode. In CONCENTRATED sulphuric acid solution, water will be oxidised at ANODE. In dilute sulphuric acid solution, water will be oxidised at anode. In dilute sulphuric acid solution, `SO_(4)^(2-)` ion will be oxidized to tetrathionate ion at anode. Solution :In dilute sulphuric acid solution, water will be oxidised at anode.