E_(Cell)^(Theta) for some half cell reactions are given below. On the basis of these mark the correct anwer. (i) H^(+)(aq)+e^(-)to(1)/(2)H_(2)(g),E_(Cell)^(Theta)=0.00V (ii) 2H_(2)O(l)toO_(2)(g)+4H^(+)(aq)+4e^(-),E_(Cell)^(Theta)=1.23V (iii) 2SO_(4)^(2-)(aq)toS_(2)O_(8)^(2-)(aq)+2e^(-),E_(Cell)^(Theta)=1.96V

E_(Cell)^(Theta) for some half cell reactions are given below. On the

1.	E_(Cell)^(Theta) for some half cell reactions are given below. On the basis of these mark the correct anwer. (i) H^(+)(aq)+e^(-)to(1)/(2)H_(2)(g),E_(Cell)^(Theta)=0.00V (ii) 2H_(2)O(l)toO_(2)(g)+4H^(+)(aq)+4e^(-),E_(Cell)^(Theta)=1.23V (iii) 2SO_(4)^(2-)(aq)toS_(2)O_(8)^(2-)(aq)+2e^(-),E_(Cell)^(Theta)=1.96V
Answer» In dilute SULPHURIC acid solution, HYDROGEN will be reduced at cathode. In concentrated sulphuric acid solution, WAER will be oxidised at anode. In dilute sulphuric acid solution, WATER will be oxidised at anode. in dilute sulphuric acid solution, `SO_(4)^(2-)` ion will be oxidised to tetrathionate ion at anode. Solution :Indilute `H_(2)SO_(4)`, (acidulated water), `H^(+)` ions are reduced to `H_(2)` at cathode, i.e., (a) and `H_(2)O` is oxidized to `O_(2)` at anode i.e., (c) reaction (III) occurs when `H_(2)SO_(4)` is concentrated