1.

E_(Cu)^(0)=+0.34V and E_(Ag)^(0)=+0.8V" calculate "E_(cell")^(0).

Answer»

SOLUTION :`E_("CELL")^(0)overset(oplus_(0))(E)-overset((-0)_(0))(E) =E_(Ag)-E_(Cu)`
=+0.8-0.34
`E_("cell")^(0)=+0.46V`


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