1.

E^(@)Cu=0.34V,E_(Zn)^(@)=-0.76V. A Daniell cell contains 0.1M ZnSO_(4) solution and 0.01 M CuSO_(4) solution at its electrodes. E.M.F. of the cell is

Answer»

1.10V
1.04V
1.16V
1.07V

Solution :`ZN|Zn^(2+)||CU^(2+)|Cu`
`Zn+Cu^(2+)+rarrZn^(2+)+Cu`
`E_("cell")^(@)=E_(Cu^(2+)._(//Cu))-E_(Zn^(2+)._(//Zn))^(@)`
`=0.34-(-0.76)=1.10V`
`E_("cell")=E_("cell")^(@)(0.0591)/(2)"LOG"([Zn^(2+)])/([Cu^(2+)])`
`=1.10V-(0.0591V)/(2)"log"(0.1)/(0.01)`
`=10.7045V`


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