E) Find the greatest number that will divide 93, 111 and 129 leaving r

1.	E) Find the greatest number that will divide 93, 111 and 129 leaving remainder 3 in each case.
Answer» Answer: Step-by-step explanation: Since Remainder is 3 in each CASE numbers are 93 – 3 = 90 111 – 3 = 108 129 – 3 = 126 Required number will be HCF of 90,108 and 126 HCF of 90 and 108 So. Greatest number will be =18

E) Find the greatest number that will divide 93, 111 and 129 leaving remainder 3 in each case.

Answer»

Answer:

Step-by-step explanation:

Since Remainder is 3 in each CASE numbers are 93 – 3 = 90 111 – 3 = 108 129 – 3 = 126 Required number will be HCF of 90,108 and 126 HCF of 90 and 108 So. Greatest number will be =18

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E) Find the greatest number that will divide 93, 111 and 129 leaving remainder 3 in each case.​

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E) Find the greatest number that will divide 93, 111 and 129 leaving remainder 3 in each case.