1.

E^(@) for Fe^(2+)+2e^(-) too Feis -0.4 volts and E^(@) for Zn^(2+)+2e^(-) to Znis -0.76 volts . Its means that

Answer»

FE is more electropositive
ZN is more electropositive
Zn is more electronegative
Fe is more electronegative

Solution :`E_("RED")^(0)Fe gt E_("red")^(0)Zn`


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