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E^@ for the half cell reactions are as,Zn→Zn^(2+) +2e,E^@=+0.76VFe→Fe^(2+)+2e,E^@=+0.41VThe E^@ for the cell reaction.Fe^(2+) +ZnrarrZn^(2+)+Fe: |
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Answer» `-035V` |
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