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`E^(@)` in the given diagram isA. `0.51 V`B. `0.61 V`C. `0.71 V`D. `0.81 V` |
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Answer» Correct Answer - B `ClO_(3)^(-)+2H_(2)O+4e^(-)rarr ClO^(-)+4OH^(-) Delta G_(1)^(@)` `ClO^(-)+H_(2)O+e^(-)rarr(1)/(2)Cl_(2)+2OH^(-) Delta G_(2)^(@)` `(1)/(2)Cl_(2)+e^(-)rarr Cl^(-) Delta G_(3)^(@)` `ClO_(3)^(-)+3H_(2)O+6e^(-)rarr Cl+6OH^(-)` `Delta G^(@)=Delta G_(1)^(@)+Delta G_(2)^(@)+Delta G_(3)^(@) , Delta G = -nF E^(@)` `-6FE^(@)=-4Fxx0.54-1Fxx0.45-1Fxx1.07` `E^(@)=+(3.68)/(6)=0.61` |
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