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E_(MnO_4^(-)// Mn^(+2), H^(+)) can be 0.48 V greaterthan from E^@ value if the [MnO_4^(-)] is equal to [Mn^(+2)] at a P^(H) of ___________ |
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Answer» Solution :`MnO_4 + 8 H^(oplus) + 5e^(-) to Mn^(+2) + 4H_2O , E= E^(0) - (0.0591)/(5) log""([Mn^(+2)])/([MnO_4^(-)][H^(oplus)]^(8))` ` (E-E^(0)) = (-0.0591)/(2) log [H^(oplus)]^(-8) , 0.48 = -(0.0591)/(5) xx (-8) log[H^(oplus)]` ` P^(H) - log[H^(oplus)] = [(0.048 xx 5)/(0.0591xx 8)] = 5.076` |
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