1.

E_(ni^(2+)//Ni)^(@)=-0.25 VE_(Au^(3+)//Au)^(@)=1.50 v The emf of the voltaic cell Ni//Ni^(2+)(1.0 M)||Au^(3+)(1.0 M)|Au is

Answer»

1.25 V
`-1.75 V`
1.75V
2.0 V

Solution :EMF of the CELL = `1.50 -(-0.25) = 1.75 V`


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