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| 1. |
E^(@) of Cu is + 0.34 V while that of Zn is – 0.76 V. Explain. |
| Answer» Solution :High ionisation enthalpy to change Cu (s) to `Cu^(2+)` is not balanced by hydration enthalpy. Therefore, it EXHIBITS a positive `E^(@)` value. However, Zn exhibits a lower value of ionization enthalpy because a stable `3d^(10)` CONFIGURATION is attained after LOSING two electrons. The hydration energy for `Zn^(2+)` is COMPARABLE to that of `Cu^(2+)`. Therefore, `Eo^(@)` for Zn is negative. | |