1.

E^(@) value of following half-cell in standard conditions are given as follows : [E_(Fe^(3+)|Fe^(2+))^(o)=0.77V,E_(Sn^(2+)|Sn)^(o)=-0.14V] by using such value calculate potential of given reaction ? Sn_((S))+2Fe_((aq))^(3+) to 2Fe_((aq))^(2+)+Sn_((aq))^(2+).

Answer»

0.91V
1.40V
1.68V
0.63V

Solution :`E^(o)=E_(FE^(2+)|Fe^(2))^(o)-E_(SN^(2+)|Sn)^(o)`
`=0.77-(-0.14)=0.91V`.


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