E^(@)Zn^(2+)//Zn = -0.77V. What is the 'E' value of the electrode cont – InterviewSolution

1.	E^(@)Zn^(2+)//Zn = -0.77V. What is the 'E' value of the electrode containing 0.01M Zn^(2+) ions
Answer» ANSWER :`-0.83 V`

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