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Each of the four particles move along x axis. Their coordinates (in metres) as function of time (in seconds) are given by {:("Particle 1" : x(t)=3.5-2.7t^(3)"Particle 2" : x(t)=3.5+2.7t^(3)),("Particle 3" : x(t)=3.5+2.7t^(2)"Particle 4" : x(t)=3.5-3.4t-2.7t^(2)):} which of these particles is speeding up for t gt 0? |
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Answer» All four `(dx)/(dt)=0` for particles 1, 2 and 3 and `|(d^(2)X)/(dt^(2))|GT 0` for `t gt 0` and `(dx)/(dt)=-3.4 m//s` for particle 4 and `(d^(2)x)/(dt^(2))` isnegative for `t gt 0` Therefore `t gt 0 , |(dx)/(dt)|` is INCREASING in all. |
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