Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g/m. When both the strings vibrate simultaneously the number of beats is :

Each of the two strings of length 51.6 cm and 49.1 cm are tensioned se

1.	Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g/m. When both the strings vibrate simultaneously the number of beats is :
Answer» 7 8 3 5 Solution :Use V = `sqrt(T// m ) and v_(1) = (V)/(lambda_(1)) ` and `v_(2) = V//lambda_(2)THEREFORE B = \| v_(1) - v_(2) \| . ` CORRECT choice is a .

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Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g/m. When both the strings vibrate simultaneously the number of beats is :

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