Each of the two strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is same and equal to `1 g//m`. When both the strings vibrate simultaneously, the number of beats isA. 3B. 5C. 7D. 8

Each of the two strings of length `51.6 cm` and `49.1 cm` are tensione

1.	Each of the two strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is same and equal to `1 g//m`. When both the strings vibrate simultaneously, the number of beats isA. 3B. 5C. 7D. 8
Answer» Correct Answer - C `Deltav=(V)/(2l_(1))-(V)/(2l_(2))=(V)/(2)[(1)/(l_(1))-(1)/(l_(2))]` `=(1)/(2)sqrt((T)/(mu)){(1)/(l_(1))-(1)/(l_(2))}`

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Each of the two strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is same and equal to `1 g//m`. When both the strings vibrate simultaneously, the number of beats isA. 3B. 5C. 7D. 8

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