EB15. If ABCD is a square and DCE is an equilateraltriangle in the giv

1.	EB15. If ABCD is a square and DCE is an equilateraltriangle in the given figure, then ZDAE is equal to(a) 45°(b) 30°(c) 15°(d) 221.DC2A АB
Answer» Answer: 15 Step-by-step explanation:Given, ABCD is a SQUARE. DCE is an equilateral triangle. ABCD is a square, AB=BC=CD=DA DCE is an equilateral triangle, DC=DC=CE HENCE, AB=BC=CD=DA=CE=DC Now, In △ADE, AD=DE Thus, ∠AED=∠DAE=x ∠ADE=∠ADC+∠EDC ∠ADE=90+60 ∠ADE=150 ∘ Sum of angles of triangle ADE = 180 ∠ADE+∠AED+∠DAE=180 150+x+x=180 x=15 ∘ Hence, ∠DAE=15 ∘ PLEASE MARK AS BRAINLIEST

EB15. If ABCD is a square and DCE is an equilateraltriangle in the given figure, then ZDAE is equal to(a) 45°(b) 30°(c) 15°(d) 221.DC2A АB

Answer»

Answer: 15

Step-by-step explanation:Given, ABCD is a SQUARE. DCE is an equilateral triangle.

ABCD is a square,

AB=BC=CD=DA

DCE is an equilateral triangle,

DC=DC=CE

HENCE, AB=BC=CD=DA=CE=DC

Now, In △ADE,

AD=DE

Thus, ∠AED=∠DAE=x

∠ADE=∠ADC+∠EDC

∠ADE=90+60

∠ADE=150

∘

Sum of angles of triangle ADE = 180

∠ADE+∠AED+∠DAE=180

150+x+x=180

x=15

∘

Hence, ∠DAE=15

∘

PLEASE MARK AS BRAINLIEST