1.

Efficiency of a Carnot engine is `50%` when temperature of outlet is `500 K`. In order to increase efficiency up to `60%` keeping temperature of intake the same what is temperature of outlet?A. 200KB. 400KC. 600KD. 800K

Answer» Correct Answer - B
`eta_(1)=1-(T_(2))/(T_(1)), eta_(2)=10(T_(2)^(1))/(T_(1)`


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