1.

Efficiency of engine is eta_(1)" at T_(1)= 200^(@)C and eta_(2)" at "T_(1)=0^(@)C and T_(2)=-200 K. Find the ratio of (eta_(1))/(eta_(2)) :

Answer»

`1 cdot 00`
`0 cdot 577`
`0 cdot 721`
`0 cdot 34`

Solution :`eta_(1)=1-(273)/(473)=(200)/(473)`
`eta_(2)=1-((-200+273))/(273)=(200)/(273)`
`therefore (eta_(1))/(eta_(2))=(273)/(473)=0 cdot 577`
So, correct choice is (b).


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