1.

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1). Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s. Each photon has a momentum p = (hf)/(c), although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda= (h)/(p), where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg. A proton is 1836 times heavier than an electron and has same charge as that of electron. For what velocity of the proton will its de Broglie wavelength be 4455 Å

Answer»

`10^(6) m.s^(-1)`
`10^(7) m.s^(-1)`
`3 XX 10^(6) m.s^(-1)`
`3 xx 10^(7) m.s^(-1)`

ANSWER :C


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