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Eis a point on side AC of AABC with AB = AC. Show that CE |
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Answer» Answer: Given - AB = AC To PROVE -- BD > CD Proof -- Since AB = AC ∠ABC = ∠ACB (By Isosceles Triangle property) ----(i) Here clearly, ∠ABC > ∠CBD ∠ACB > ∠CBD ---from (i) ∠DCB > ∠CBD BD > CD (Angle opposite to greater SIDE is greater in a triangle) Hence Proved! Hope This Helps You! Step-by-step explanation: plzz mark as brainlist |
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