1.

एक ट्रान्सफॉर्मर की प्राथमिक और द्वितीयक कुण्डलियो के फेरो की संख्या क्रमशः `N_(p)" और "N_(s)` है । द्वितीयक कुण्डली का प्रतिरोध `R_(s)` है। प्राथमिक परिपथ के दृष्टिकोण से लोड का तुल्य प्रतिरोध है -A. `(R_(s)N_(s))/(N_(p))`B. `R_(s)((N_(s))/(N_(p)))^(2)`C. `(R_(s)N_(p))/(N)`D. `R_(s)((N_(p))/(N_(s)))^(2)`

Answer» `(V_(s))/(V_(p))=(N_(s))/(N_(p))=(I_(p))/(I_(p))," परन्तु "(V_(s))/(V_(p))=(R_(s)I_(p))/(R_(p)I_(p))`
अतः `(N_(s))/(N_(p))=(R_(s))/(R_(p))xx(N_(p))/(N_(s))`


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