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Electric field due to infinite long straight wire of linear charge density λ varies with ⊥ distance of point from the wire as * |
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Answer» Given:An infinite long wire of linear CHARGE density λTo Find:Variation of electric field with perpendicular distance of a point from the wireSolution:Imagine a cylindrical gaussian surface around the wire.Refer to the attached diagramCurved surface area of the cylinder = 2πrl(where 'r' is the radius and 'l' is the LENGTH of the cylinder)Since the electric field is radial, electric FLUX through both the flat ends of the cylindrical gaussian surface is zero.⇒ Flux through the total gaussian surface = Flux through the cylindrical part⇒ \oint E.dScos0 = \oint EdS∮E.dScos0=∮EdS⇒ E \oint dSE∮dS⇒ E.2πrlThe surface includes a charge (q) = λlHence, according to gaussian law,E2πrl = λl/ε₀⇒ E = λ/2πε₀rThus, Electric field due to infinite long straight wire of linear charge density λ VARIES with ⊥ distance of point from the wire as E = λ / 2πε₀rMark me BRAINLIEST |
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