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Electric field of an infinitely long conductor of charge density λ, is given by E = λ/(2πεh).aN. State True/False.(a) True(b) FalseThis question was posed to me in my homework.The origin of the question is Electric Field Intensity topic in chapter Electrostatic Fields of Electromagnetic Theory |
Answer» RIGHT option is (a) True To explain I WOULD say: The electric FIELD intensity of an infinitely long conductor is given by, E = λ/(4πεh).(SIN α2 – sin α1)i + (cos α2 + cos α1)j For an infinitely long conductor, α = 0. E = λ/(4πεh).(cos 0 + cos 0) = λ/(2πεh).aN. |
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