1.

Electric field of electromagnetic wave is represented by E = 50 sin (omega t -(x)/(c ))NC^(-1). Intensity of wave is ….. Wm^(-2).

Answer»

(A) 50
(B) `1.1xx10^(-8)`
(C) `3.3`
(D) `5.5xx10^(-19)`

SOLUTION :Here `E_(m)=50 NC^(-1)`
`therefore E_(rms)=(50)/(sqrt(2))NC^(-1)`
Intensity of wave,
`I=c in_(0)E_(rms)^(2)`
`=(3xx10(8)xx8.85xx10^(-12)xx2500)/(2)=3.3 Wm^(-2)`


Discussion

No Comment Found

Related InterviewSolutions