1.

Electric field on surfaces of twospheres of radius r_(1) and r_(2) are same, then ratio of their electric potential will be ....... .

Answer»

`(r_(1)^(2))/(r_(2))`
`(r_(2)^(2))/(r_(1)^(2))`
`(r_(1))/(r_(2))`
`(r_(2))/(r_(1))`

Solution :`E_(1)=(KQ)/(r_(1)^(2))=(kq)/(r_(1))xx(1)/(r_(1))=(V_(1))/(r_(1))`
`E_(2) =(kq)/(r_(2)^(2))=(kq)/(r_(2))xx(1)/(r_(2))=(V_(2))/(r_(2))`
but `E_(1)=E_(2):. (V_(1))/(r_(1))=(V_(2))/(r_(2)):. (V_(1))/(V_(2))=(r_(1))/(r_(2))`


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