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Electric flux coming out of a single Na^+ ion is _________ Nm^2C^-1(a) 1.8*10^-8(b) 1.8*10^-10(c) 5.4*10^-8(d) 3.6*10^-8I had been asked this question in final exam.Asked question is from Application of Gauss’s Law in chapter Charges and Fields of Physics – Class 12

Answer»

Right ANSWER is (a) 1.8*10^-8

For explanation I would say: A single Na^+ ION MEANS a single sodium atom without an electron. The charge of the ion is the same as the charge of an electron but positive i.e. +1.602*10^-19C. Therefore, applying Gauss’s LAW, electric flux coming out of the ion = \(\frac {charge \, of \, the \, ion}{\varepsilon}\). Substituting the VALUES, we get flux = 1.8*10^-8 Nm^2C^-1.



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