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Electrode potential for Mgelectrode varies accordingto the euation E_(mg^(2+)//Mg)=E_(Mg^(2+)//Mg)-(0.059)/(2) log (1)/[(Mg^(2+))] the graphof E_(Mg^(2+)//Mg) "vs" log [Mg^(2+)]is

Answer»




Solution :THEGRAPH of `E_(mg^(2+)//mg) "VS" log [Mg^(2+)]` is shown by theoption (B) it is the straightlinegraphwith INTERCEPT


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