Electrode potential of Zn^(2+)//Zn is -0.76V and that of Cu^(2+)//Cu i – InterviewSolution

1.	Electrode potential of Zn^(2+)//Zn is -0.76V and that of Cu^(2+)//Cu is +0.34V. The EMF of the cell constructued between these two electrodes is
Answer» 1.10V 0.42V `-1.1V` `-0.42V` SOLUTION :`E_(CELL)^(@)=E_("CATHODE")^(@)-E_("ANODE")^(@)=0.34-(0.76)=1.10V`

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