Electrolysis involves electronation and deelectronation at the respective electrodes. Anode of electrolytic cell is the electrode at which deelectronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is discharged. Discharge potential of an ion refers forE_(OP)^0 or E_(RP)^0 as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolyis i.e W=(Eit)/(96500) During electrolysis of HCOONa_((aq)) , the gas librated at anode and cathode are respectively.

Electrolysis involves electronation and deelectronation at the respect

1.	Electrolysis involves electronation and deelectronation at the respective electrodes. Anode of electrolytic cell is the electrode at which deelectronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is discharged. Discharge potential of an ion refers forE_(OP)^0 or E_(RP)^0 as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolyis i.e W=(Eit)/(96500) During electrolysis of HCOONa_((aq)) , the gas librated at anode and cathode are respectively.
Answer» `H_2,CO_2` and `O_2` `H_2,CO_2` and `O_2` `H_2` and `O_2` `O_2` and `H_2` SOLUTION :Equivalent conductance of `N//10` NaCl solution `Lambda_v` = Sp. Conductivity `xx` dilution =0.0092 `xx` 10,000=108`ohm^-1` `Lambda_oo`= `lambda_(Na^+)+ lambda_(Cl^-)`= 43.0 +65.0 = 108`ohm^-1` Degree of dissociation, `alpha`= `Lambda_v/Lambda_oo` =92/108= 0.85