1.

Electrolysis is an important technique for extraction of metals and each low of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order give below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order: SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When aqueous solution of cuprous bromide is electrolysed the product obtained a cathode will be

Answer»

CU
`H_(2)`
`Br_(2)`
`O_(2)`

SOLUTION :`Cu_(2)Br_(2) to 2CU^(+2)+2Br^(-) "At NODE" , 2Br^(-) to Br_(2)^(-)+2E^(-) , "At Cathode": 2Cu^(+)+2e^(-) to 2Cu`


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