1.

Electrolysis is an important technique for extraction of metals and each low of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order give below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order: SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When aqueous NaCl is electrolysed by using Hg electrode, the product obtained at cathode is

Answer»

NA-Hg amalgam
Na
`H_(2)`
Hg

Solution :In th presence of Hg the discharge potenetial of `Na^(+)` decreases and it dcharged FIRST.
`2NaCl to 2Na^(+)+2Cl^(-)`
At Anode `: 2Cl to Cl_(2)+2e^(-):` Ato CATHODE `Na^(+)+Hg+e^(-) to Na-Hg` Sodium amalaga.


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