Electrolysis is an important technique for extraction of metals and each low of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order give below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order: SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When cone. H_(2)SO_(4) is electrolysed with high current density using Pl clectrodes, the product obtained at anodes

Electrolysis is an important technique for extraction of metals and ea

1.	Electrolysis is an important technique for extraction of metals and each low of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order give below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order: SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When cone. H_(2)SO_(4) is electrolysed with high current density using Pl clectrodes, the product obtained at anodes
Answer» `SO_(2)` `SO_(3)` `O_(2)` `H_(2)S_(2)O_(8)` Solution :`2H_(2)SO_(4) to 2H^(+) HSO_(4)^(-)` At ANODE `: 2HSO_(4)^(-) to H_(2)S_(2)O_(8)+2e^(-)`: At CATHODE `:2H^(+)-2e^(-) to H_(2)`