1.

Electrolysis of a solution of HSO_(4)^(-) ions produces S_(2)O_(8)^(2) .Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mol of S_(2)O_(8)^(2-) per hour ?

Answer»

71.47 A
35.7 A
142.96 A
285.93 A

Solution :`2HSO_(4)^(-) RARR S_(2)O_(8)^(2-) + 2H^(+)+2E^(-)` So, required rate=1 MOL `S_(2)O_(8)^(2) //hr =2` mol `HSO_(4)^(-)` / hr
`=(2xx96500 C)/(3600s) = (2 xx 965) /(36) Lambda =53.6 A`
So, required CURRENT`=(4)/(3) xx 53.6 A =71. 48 A`


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