Electrolysis of a solution of MnSO_(4) in aqueous sulphuric acid is a method for the preparation of MnO_(2) as the per reaction, Mn^(2+) (aq.)+2H_(2)O rarr MnP_(2) +2H^(+) (aq.) +H_(2) Passing a current of 27 A for 24 hours gives one kg of MnO_(2). what is the value of current efficiency ? Write the reactions taking place at the cathode and at the anode.

Electrolysis of a solution of MnSO_(4) in aqueous sulphuric acid is a

1.	Electrolysis of a solution of MnSO_(4) in aqueous sulphuric acid is a method for the preparation of MnO_(2) as the per reaction, Mn^(2+) (aq.)+2H_(2)O rarr MnP_(2) +2H^(+) (aq.) +H_(2) Passing a current of 27 A for 24 hours gives one kg of MnO_(2). what is the value of current efficiency ? Write the reactions taking place at the cathode and at the anode.
Answer» Solution :Apply `w=(Exxixxt)/(96500)` `1000=(87xxixx24xx60xx60)/(2xx96500)` `i=25.6` ampere Current efficiency `=25.6/27.0xx100=94.8 %` REACTION : `{:("Anode:",Mn^(2+) RARR Mn^(4+)+2e^(-)),("Cathode :",2H^(+) +2e^(-) rarr H_(2)):}`