1.

Electrolysis of brine gives

Answer»

`Cl_(2)`
`H_(2)`
NaOH
`Na+H_(2) + Cl_(2)`

Solution :`2NaCl RARR 2Na^(+) + 2Cl^(-)`( Ionisation ) , Anode `: 2Cl rarr Cl_(2) + 2e^(-)` ( Oxidation)
Cathode `: H_(2) O overset( 2e) ( rarr) H_(2) + 2OH^(-) `( REDUCTION)
`2Na^(+)+2OH^(-) rarr 2NaOH`


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