1.

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli-ampere current. The time required to liberate 0.01 mole of H_(2) gas at the cathode is : (1 faraday = 96500 C mol^(-1))

Answer»

`9.65 XX 10^(4)` SEC
`19.3 xx 10^(4)` sec
`28.95 xx 10^(4)` sec
`38.6 xx 10^(4)` sec

Solution :`(W)/(E) = (i xx T)/(96500)`
`0.01 xx 2 = (10 xx 10^(-3) xx t)/(96500)`
` t = 19.3 xx 10^(4)` sec


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