1.

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberated 0.01 mole of H_(2) gas at cathode is: ("1 faraday =96500"C mol"^(-1)).

Answer»

`9.65xx 10^(4)"sec"`
`19.3 xx 10^(4)"sec"`
`28.95 xx 10^(4) sec`
`38.6 xx 10^(4)" sec"`

SOLUTION :Mass of 0.01 MOL of `H_(2)=0.02g`
`W=(LT E)/(96500)`
`0.02=(10 xx 10^(-3) xx t xx 1)/(96500)`
`t=19.3 xx 10^(4)" sec"`.


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