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Electrolysis of queous potassium sulphate containing litmus, develop red colour at anode and blue colour at cathode. Why ? |
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Answer» Solution :During the electrolysis of aqueous `K_2SO_4` , the chemical CHANGES involved are, At anode (oxidation of water) = `2H_2O(L) to O_2 + 4E^(-) + 4H^(+)(aq)` At CATHODE (reduction of water) = `2H_2O (l) + 2e^(-) to H_2(g) + 2OH^(-)(aq)` Solution is ACIDIC around anode and litmus is red. Solution is basic around cathode and litmus is blue. |
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