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Electrolytic cell containing molten nickel chloride and aluminium chloride solutions are arranged in a series. If on passing same current through both the solution, if 18 gm Al is obtained then how much Ni is obtained ? (Atomic mass of Al=27 and Ni=58.5 gm mol^(-1)) |
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Answer» 58.5 gm `Al^(3+)+3e^(-) to Al_((S))` So, 3 MOL `e^(-) to 1` mol AI So, 27 gm Al required 3 F CURRENT. So for 18 gm Al, amount of electricity `=(18xx3)/(27)=2F` (ii) 2F current is also PASSED through `Ni^(2+)` solution as it is in series. `Ni^(2+)+2e^(-) to NI_((S))` |
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