1.

Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths lambda_(1), lambda_(2) emitted in the two cases is

Answer»

`7//5`
`27//20`
`27//5`
`20//7`

Solution :
`E_(1)=(hc)/(lambda_(1))=13.6 [(1)/((3)^(2))-(1)/((4)^(2))] ........(i)`
`E_(2)=(hc)/(lambda_(2))=13.6 [(1)/((2)^(2))-(1)/((3)^(2))] ......(ii)`
dividing EQ. (ii) by eq. (i)
`lambda_1/lambda_(2)=(1/4-1/9)/(1/9-1/(16))=(20)/7`


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