1.

Electron should be accelerated which voltage so that its de-Broglie wavelength will become 0.4 Å.

Answer»

9410 V
94.10 V
9.140 V
941 V

Solution :`lambda=(h)/(sqrt(2Vem))`
`v=(h^(2))/(2melambda^(2))`
`=((6.62xx10^(-34))^(2))/(2xx9.1xx10^(-31)xx1.6xx10^(-19)xx(0.4xx10^(-10))^(2))`


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