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Electrons are emitted from photo-cell with maximum speed of 4xx10^(8) cm/s .Its stopping potential will be….. (Mass of electron =9xx10^(-31) kg. |
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Answer» 30V `therefore ((1)/(2)xx9xx10^(-31)XX(4xx10^(6))^(2))/(e )=V_(0)` `therefore(9xx10^(-31)xx16xx10^(12))/(2xx1.6xx10^(-19))=V_(0)` `therefore V_(0)=45V` |
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