1.

Electrons are emitted from photo-cell with maximum speed of 4xx10^(8) cm/s .Its stopping potential will be….. (Mass of electron =9xx10^(-31) kg.

Answer»

30V
45V
59V
Information is insufficient

Solution :`(1)/(W)mv_(MAX)^(2)=eV_(0)`
`therefore ((1)/(2)xx9xx10^(-31)XX(4xx10^(6))^(2))/(e )=V_(0)`
`therefore(9xx10^(-31)xx16xx10^(12))/(2xx1.6xx10^(-19))=V_(0)`
`therefore V_(0)=45V`


Discussion

No Comment Found

Related InterviewSolutions