1.

Electrons emitted with negligible speed from an electron gun are accelerated through a potential difference V along X-axis.These electrons emerges from a narrow hole into a unifrom magnetic field B directed along the axis.However, some of the electrons emerging from the hole make slightly divergent angles as shown in figure.These paraxial electrons meet for second time on the X-axis at a distance sqrt((Npi^(2)mV)/(eB^(2))).Then find value of N.(Neglect interaction between electrons)

Answer»


SOLUTION :Pitch `=(2pimcostheta)/(qB) eV=1/2mv^(2)`
`=(2pisqrt(2meV))/(eB) (costheta~~1) rArr "pitch" =SQRT((8pi^(2)mV)/(eB^(2)))`
`:.` Distance from POINT of DIVERGENCE `=sqrt((32pi^(2)mV)/(eB^(2)))`


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