Saved Bookmarks
| 1. |
Electrons emitted with negligible speed from an electron gun are accelerated through a potential difference V along X-axis.These electrons emerges from a narrow hole into a unifrom magnetic field B directed along the axis.However, some of the electrons emerging from the hole make slightly divergent angles as shown in figure.These paraxial electrons meet for second time on the X-axis at a distance sqrt((Npi^(2)mV)/(eB^(2))).Then find value of N.(Neglect interaction between electrons) |
|
Answer» `=(2pisqrt(2meV))/(eB) (costheta~~1) rArr "pitch" =SQRT((8pi^(2)mV)/(eB^(2)))` `:.` Distance from POINT of DIVERGENCE `=sqrt((32pi^(2)mV)/(eB^(2)))` |
|