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Electrons in a television are accelerated through a potential difference of 30 kV before they strike the screen. Calculate the wavelength of the most energetic X-ray photon emitted from it. |
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Answer» Solution :If ENTIRE kinetic energy of electron is converted into a photon then it will be the most energetic photon. Hence, CORRESPONDING wavelength can be written as follows : `eV=hc//lambda` `RARR lambda=(hc)/(eV)=(6.63xx10^(-34)xx3xx10^8)/(1.6xx10^(-19)xx30000)=4.1xx10^(-11)` m `rArr lambda_"MIN"=41xx10^(-12)`m = 41 PM |
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