Elemantary unimolecular reactions have first order rate laws, elementary bimolecular reactions have second order rate laws. A rate law is often derived from a proposed mechanism by imposing the state approximation or by assuming that there is a pre -equilibrium. A proposed mechanism must be consistent with the experiment rate law. The decomposition of O_(3) obeys themechanism give below Step 1: O_(3)hArrO_(2)+(O) (both forward and backward reactions are fast) Step 2: O_(3)+(O)overset("slow")(to)O_(2)+O_(2) (ignore) backward reaction), the rate of reaction is given by

Elemantary unimolecular reactions have first order rate laws, elementa

1.	Elemantary unimolecular reactions have first order rate laws, elementary bimolecular reactions have second order rate laws. A rate law is often derived from a proposed mechanism by imposing the state approximation or by assuming that there is a pre -equilibrium. A proposed mechanism must be consistent with the experiment rate law. The decomposition of O_(3) obeys themechanism give below Step 1: O_(3)hArrO_(2)+(O) (both forward and backward reactions are fast) Step 2: O_(3)+(O)overset("slow")(to)O_(2)+O_(2) (ignore) backward reaction), the rate of reaction is given by
Answer» `k[O_(3)]^(2)[O_(2)]` `k[O_(3)]^(2)[O_(2)]^(-1)` `k[O_(3)]^(2)` `k[O_(2)]^(2)` Solution :`K_(E)=[(O_(2)][O])/([O_(3)])IMPLIES[O]=(K_(e).[O_(3)])/([O_(2)]),r=K_(1)[O_(3)][O]=r=K_(1).[O_(3)].K_(C).([O_(3)])/([O_(2)]),r=K.[O_(3)]^(2)[O_(2)]^(-1)`