1.

Elevation in boililng point was 0.52^(@)C when 6 gm of a compound X was dissolved in 100 gm of water. Molecular weight of X is (K_(b) for water is 0.52 per 1000 gm of water)

Answer»

120
60
180
600

Solution :`DELTA T_(b)=(100xx K_(b)xx W)/(m xx W) THEREFORE 0.52=(100xx5.2xx6)/(m xx 100)`
`m=(100xx5.2xx6)/(0.52xx100)=60`.


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